Dynamo For Revit 2019 Apr 2026
for i, elev in enumerate(elevations): try: level = Level.Create(doc, elev) level.Name = names[i] except: pass
elevations = [0, 3000, 6000] # in project units names = ["L1", "L2", "L3"] dynamo for revit 2019
import clr clr.AddReference('RevitServices') from RevitServices.Persistence import DocumentManager doc = DocumentManager.Instance.CurrentDBDocument for i, elev in enumerate(elevations): try: level = Level
OUT = "Levels created"
This runs in a node (from Revit > Script > Python ). dynamo for revit 2019
